(i) The given digits are 0, 1, 2, 3, 4, 5. A number will be divisible by 5 if the digit in the unit place is 0 or 5 

So the unit place can be filled by 0 or 5

(a) When the unit place is 0 it is filled in 1 way 

And so 10’s place can be filled in 5 ways (by using 1, 2, 3, 4, 5) and 100’s place can be filled in (5 – 1) 4 ways 

So the number of 3 digit numbers with unit place 0 

= 1 × 5 × 4 = 20

(b) When the unit place is 5 it is filled in 1 way 

Since 0 is given as a digit to fill 100’s place 0 should be excluded 

So 100’s place can be filled in (excluding 0 and 5) 4 ways and 10’s place can be filled in (excluding 5 and one digit and including 0) 4 ways 

So the number of 3 digit numbers with unit place 5 = 1 × 4 × 4 = 16 

∴ Number of 3 digit numbers ÷ by 5 = 20 + 16 = 36

(ii) The digits are 0 1 2 3 4 5 

To get a number divisible by 5 we should have the unit place as 5 or 0 

So the unit place (using 0 or 5) can be filled in 2 ways. 

The 10’s place can be filled (Using 0, 1, 2, 3, 4, 5) in 6 ways and the 100’s place (Using 1, 2, 3, 4, 5) can be filled in 5 ways. 

So the number of 3 digit numbers ÷ by 5 (with repetition) = 2 × 6 × 5 = 60