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How many time does the electron go round the first bohr orbit of hydrogen atoms in `1 s`?A. `6.62 xx 10^(15)`B. 100C. 1000D. 1 |
Answer» Correct Answer - A Frequency of electron revolution: `f = (m Z^(2) e^(4))/(4 epsilon_(0)^(2) n^(3) h^(3))` Put the various value to get `f = 6.62 xx 10^(15) (Z^(2))/(n^(3))` Now put `Z = 1 and n = 1` to get `f = 6.62 xx 10^(15) H z` |
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