1.

How many total possible isomers are present in the following complex ? [Co(gly)NH_(3)H_(2)O(CN)(NO_(2))]

Answer»

24
48
96
12

Solution :
`[M(AB)abcd]`
(a opp B) `IMPLIES` C, d and d, c]2
(a opp c) `implies` (b, d)(d, c)=2
(a opp d) `implies=2`
(b opp c) `implies=2`
(b opp d) `implies=2`
(c opp d) `implies=(2)/(12)`

All are O.A.
So, 48xx2=96


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