1.

How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1.0 g ?

Answer»

`2.57 xx 10^(21)`
`1.28 xx 10^(21)`
`1.71 xx 10^(21)`
`5.14 xx 10^(21)`

Solution :No. of NaCl molecules in a unit CELL = 4
MASS of unit cell `= ( 4 xx 58.5)/( 6.022 xx 10^(23))`
No. of unit CELLS in 1 g
` = ( 1 xx 6.022 xx 10^(23))/( 4 xx 58.5) = 2.57 xx 10^(21)` unit cells


Discussion

No Comment Found

Related InterviewSolutions