1.

How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic masses : Na = 23, Cl = 35.5]

Answer»

`2.57 xx 10^(21)`
`5.14 xx 10^(21)`
`1.28 xx 10^(21)`
`1.71 xx 10^(21)` 

SOLUTION :Number of NaCl units per unit CELL = 4
Number of NaCl units in 1 g NaCl `= 1/58.5 xx N_A`
`therefore`Number of unit cell in 1 g NaCl `= (N_A)/(58.5 xx 4)`


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