1.

How many unit cells are present in a cube-shaped ideal crystal ofNaCI of mass 1 .00 g? [Atomic masses : Na = 23, Cl = 35.5]

Answer»

`5.14xx10^(21)` unit CELLS
`1.28xx10^(21)` unit cells
`1.71xx10^(21)` units cells
`2.57xx10^(21)` unit cells

Solution :Number of formulas in CUBE shaped crystals
`=(1.0)/(58.5)xx6.02xx10^(23)` since in NACL TYPE of structure.
4 formula units form 'a' cell
`therefore `unit cells`=(1.0xx6.02xx10^(23))/(58.5xx4)=2.57xx10^(21)` unit cells.


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