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How many unit cells of KBr are present in a 1.00 mm^(3) of KBr, KBr crystallizes in NaCl type of crystal lattice and its density is 2.75 g/cm^(3) |
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Answer» Solution :In aunit CELL of KBr, there are four FORMULA units of KBr. Therefore, density`(rho)=(4xx119)/(6.023xx10^(23)xxa^(3))=2.75 `implies a^(3)=2.778xx10^(-22) cm^(3)=2.778xx10^(-19)MM^(3)` `implies` No. of unit CELLS per `mm^(3)=(10^(19))/(2.778)=3.6xx10^(18)` |
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