1.

How may chiral compounds are possible on monochlorination of 2-methylbutane?

Answer»

8
2
4
6

Solution :There are two CHIRAL carbo atoms for the MOLECULAR formula.
`overset(Cl)overset(|)(C)H_(2)-UNDERSET(CH_(3))underset(|)overset(**)(C)H-CH_(2)-CH_(3)" "CH_(3)-underset(CH_(3))underset(|)(C)H-overset(Cl)overset(|)overet(**)(C)H-CH_(3)` there ar in all four chiral compounds possible `(2^(N)=2^(2)=4)`.


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