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How may methyl bromide be preferentially converted to methyl cyanide and methylisocyanide ? |
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Answer» Solution :REACTION with KCN produces methyl cyanide and with `AGCN` produces methyl isocyanide. The reactions are given as under: <BR> `CH_(3)Br + KCN to underset("Methyl cyanide") (CH_(3)CN ) + KBr ` `CH_(3)Br + AgCN to underset("Methyl isocyanide") (CH_(3)NC ) + AgBr ` |
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