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How might you separate the following pairs of ions by addition of singles reagent include formula for the major products of the reactions(a)Fe^(3+)andNa^(+)(b)Cr^(3+)andFe^(3+)(c )Fe^(2+)and Cu^(2+) |
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Answer» Solution :(a)`FE^(3+)`and Na Add KOH(excess),`Fe^(3+)`is precipitaed as `Fe(OH)_(3)` Na remains in solution `Fe^(3+)(aq)+3OH(aq)TOFE(OH)_(3)(s)darr` (b) `CR^(3+)` and `Fe^(3+)` Add KOH(excess),ofaq NaOH,`Fe^(3+)` is PRECIPITATED as Fe(Oh) while `Cr(OH)_(3)` First formed dissolves in excess of aq.`NaOHFe^(3+)` `(aq)+3OH(aq)toFe(OH)_(3)(s)overset(OH)^(-))to`does not dissolve |
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