Saved Bookmarks
| 1. |
How much AgClwill be formed byadding 1.70 " g of " AgNO_(3) in 200 mL of 5 N HCl solution ? (Ag = 108, N = 14 , O= 16) |
|
Answer» Solution :Equivalent of `AgNO_(3) = (1.70)/(170) = 0.71 ` m.e of HCl solution = `5 xx 200 = 1000` ` :. ` equivalent of HCl solution ` = 1000/(1000) = 1 ` Since equivalent of `AgO_(3)`is less than the eq. of HCl , equivalent of AgCl = eq. of `AgNO_(3) = 0.01 ` ` :. ` wt. of AgCl = `0.01 xx 1435` ` = 1.435 G ` |
|