1.

How much current in columb is required to decrease 1 mol of Cr_(2)O_(7)^(-2) from the following reaction ? Cr_(2)O_(7)^(-2)+14H^(+) +6e^(-) to 2Cr^(+3)+7H_(2)O

Answer»

5,80,000 COLUMB
5,79,500 columb
5,80,500 columb
5,79,000 columb

Solution :`Cr_(2)O_(7)^(-2)+14H^(+)+6e^(-) to 2Cr^(+3)+7H_(2)O`
`6xx96500C=5,79,000` columb current is required.


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