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How much electricity in terms of Faraday is required to produce 40.0 g of Al from molter Al_(2)O_(3)? |
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Answer» SOLUTION :`Al^(3+)+3e^(-)rarrAl` 27 gram of Al require ELECTRICITY = 3F 40 gram of Al require electricity `=(3F)/(27)xx40=4.44F` |
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