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How much electricity in terms of Faraday is required to produce `20 g` of `Ca` from molten `CaCl_(2)` ?A. 1.5B. 2C. 1D. 4 |
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Answer» Correct Answer - C `"Eq. of Ca",(w)/(E)=(ixxt)/(96500),Ca^(2+)+2erarrCa` `thereforeE_(Ca)=(40)/(2)or (20)/(40//2)=(ixxt)/(96500)` `ixxt=1xx96500=1F` |
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