1.

How much emf is induced in a coil of self-inductance 2H if the current in it.is changing at the rate of 2 As^(-1) ?

Answer»

SOLUTION :`L = 2H, (DI)/(dt) = 2As^(-1)`
We have `EPSI = L (dI)/(dt)`
`epsi = 2 xx 2 `
` epsi = 4V`


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