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How much emf is induced in a coil of self-inductance 2H if the current in it.is changing at the rate of 2 As^(-1) ? |
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Answer» SOLUTION :`L = 2H, (DI)/(dt) = 2As^(-1)` We have `EPSI = L (dI)/(dt)` `epsi = 2 xx 2 ` ` epsi = 4V` |
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