1.

How much energy is required to send the electron at infinite distance from the n = 3 orbit in He^(+) ?

Answer»

12.08 eV
6.04 eV
30.2 eV
3.02 eV

Solution :The ENERGY REQUIRED `E_(N)=-13.6xx(Z^(2))/(n^(2))eV`
For `He^(+)` n=3 and z=2
`:.E_(He)=(-13.6xx4)/(9)=-6.04 eV`
The total energy should be equal to 6.04 eV given to electron of Het to be zero and hence electron goes infinite distance AWAY.


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