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How much energy will be necessary for making a body of 500 kg escape from the earth `[g=9.8 ms^(2)," radius of earth "=6.4xx10^(6)m]`A. `6.4xx10^(8)J`B. `3.2xx10^(10)J`C. `6.4xx10^(12)J`D. `3.2xx10^(6)J` |
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Answer» Correct Answer - B P.E. of the ody at the surface of the earth, `U=-(GMm)/(R )` but `g=(GM)/(R^(2)) therefore (GM)/(R )=gR` `=-(3.2xx10^(10)J)` Thus an energy of `3.2xx10^(10)J` should be given to the body in the form of K.E., so that it will escape from the earth. |
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