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How much glucose, C_(6)H_(12)O_(6) must be dissolved per litre of the solution that yields osmotic pressure os 2.72 atmospheres at 298 K ? R=0.0821 L atm K^(-1). |
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Answer» `V=1.0L, pi=2.72 ATM, R=0.0821" L atm K"^(-1)mol^(-1), T=298K, W_(B)=?` `piV=n_(B)RT or n_(B)=(piV)/(RT),W_(B)/M_(B)=(piV)/(RT)` `W_(B)=(M_(B)xxpixxV)/(RT)=((180" g mol"^(-1))xx(2.72" atm")xx(1L))/((0.0821"L atm K"^(-1)mol^(-1))xx(298 K))=20.0116 g.` |
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