1.

How much gram of acid should be present in 100 mL volume of solution to obtain decimolar solution having 200 gm/mole molecular mass of diabasic acid ?

Answer»

20 gm
1 gm
2 gm
10 gm

SOLUTION :Decimolar means 0.1 M
`M=("MOLE")/("Liter")=(w)/(200)xx(1)/(100)xx1000 =0.1`
`therefore 0.1=(w)/(20) therefore 2=2` gm.


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