InterviewSolution
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InterviewSolution
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How much heat (in joule) is required to raise the temperature of `205 g` of water from `21.2^(@)C` to `91.4^(@)C`. Specific heate of water is `4.18 J g^(-1) .^(@)C^(-1)` Strategy : The specific heat of a substance is the amount of heat required to raise the temperature of `1g` of the substance by `1^(@C`. Thus Specific heat `= (("Amount of heat in joules"))/(("Mass of substance in grams")("Temperature change in" .^(@)C))` Rearrangement gives. Amount of heat `(q) =` Mass of substance `(m) xx` Specific heat `(c ) xx` Temperature change `(Delta T)` |
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Answer» Accroding to `q = mc Delta T` `= (205 g) (4.18 J g^(-1) .^(@)C^(-1)) (91.4^(@)C - 21.2^(@)C)` |
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