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InterviewSolution
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How much heat is released when `850 kg` of ammonia is produced according to the following thermochemical equation? `N_(2) (g) + 3 H_(2) (g) rarr 2 NH_(3) (g)`, `Delta_(1) H^(@) = -91.8 kJ` Strategy : To do the calculation, we must convert grams of `NH_(3)` to moles of `NH_(3)`, and then to kilojoules of heat. Grams of `NH_(3) rarr ` Moles of `NH_(3) rarr` Kilojoules of heat |
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Answer» Step 1: Calculating moles of `NH_(3)` `n_(NH_(3)) = ("Mass"_(NH_(3)))/("Molar mass"_(NH_(3))` ` = (850 xx 10^(3) g)/(17 g NH_(3) mol^(-1))` `5 xx 10^(4) mol` Step 2: 2 mol `NH_(3)` formation releases `91.8 kJ`. This, the formation of `5 xx 10^(4) mol NH_(3)` will release `(91.8 Kj)/(2 mol) xx 5 xx 10^(4) mol = 2.30 xx 10^(6) kJ` |
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