1.

How much heat is required to raise the temperature of a 0.04 kg stainless steel spoon from 20^(@)C to 50^(@)C if the specific heat of stainless steel is 0.50kJ//kg*""^(@)C ?

Answer»

200J
400J
600J
800J

Solution :USE the EQUATION `Q=mvDeltaT`.
`Q=(0.04kg)(0.50kJ//kg*""^(@)C)(50^(@)C-20^(@)C)=0.6kJ=600J`


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