1.

How much is 4x ^2+2y greater than 4y^2+ 2x​

Answer»

ANSWER:

Your answer will be x²-y²>1/2(x-y)

Step-by-step explanation:

=4x²+2y>4y²+2x

=4x²-4y²>2x-2y

=4(x²-y²)>2(x-y)

= x²-y²>2/4(x-y)

=x²-y²>1/2(x-y)

I HOPE this will help you.....

PLZZZ follow me and mark me as BRAINLIEST......



Discussion

No Comment Found