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How much is 4x ^2+2y greater than 4y^2+ 2x |
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Answer» Your answer will be x²-y²>1/2(x-y) Step-by-step explanation: =4x²+2y>4y²+2x =4x²-4y²>2x-2y =4(x²-y²)>2(x-y) = x²-y²>2/4(x-y) =x²-y²>1/2(x-y) I HOPE this will help you..... PLZZZ follow me and mark me as BRAINLIEST...... |
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