1.

How much marble of 96.5% purity would be required to prepare 10 litres of carbon dioxide at STP when the marble is acted upon by dilute hydrochloric acid?

Answer»


Solution :`underset(100g)(CaCO_(3))+2HCL rarrCaCl_(2)+H_(2)O+underset("22.4 at STP")(CO_(2))`
10 L of `CO_(2)` at STP will be obtained from pure `CaCO_(3)=(100)/(22.4)xx10=44.64g`
`"Impure marble required "=(100)/(96.5)xx44.64=46.26g`


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