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How much momentum will a dumb-bell of mass `10kg` transfer to the floor if it falls a height of `80 cm`? Take its downward acceleration to be `10 m//s^(2)`. |
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Answer» Correct Answer - 40 kg Mass of the dumbbell, m = 10 kg Distance covered by the dumbbell, s = 80 cm = 0.8 m Acceleration in the downward direction, `a = 10 m//s^(2) ` Initial velocity of the dumbbell, u = 0 Final velocity of the dumbbell (when it was about to hit the floor) = v According to the third equation of motion: ` v^(2)= u^(2) + 2as` ` v^(2)= 0 + 2 (10) 0.8 ` v= 4 m/s Hence, the momentum with which the dumbbell hits the floor is = mv ` = 10 xx 4 kg ms^(-1)` ` = 40 kg ms^(-1)` |
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