How much of NaOH is required to neutralise 1500 cm^(3)of 0.1 N HCI? (N – InterviewSolution

1.	How much of NaOH is required to neutralise 1500 cm^(3)of 0.1 N HCI? (Na = 23)
Answer» 40 G 4 g 6 g 60 g Solution :`1500 cm^(3)` of 0.1 N HCL `=0.1/1000 xx 1500 = 0.15` g eq. It will NEUTRALISE `NaOH = 0.15 g eq. = 0.15 xx 40 g = 6 g`

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