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How much of NaOH is required to neutralise 1500 crr' of 0.1 N HCl? (N.-23)A)40 g13.B) 4 gCy6g |
Answer» Weight of NaOH = N* E.W. * V/1000 Put the values in the above formula Weight of NaOH required.= 0.1 *40 *1500/1000 = 6 gm |
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