1.

How much of NaOH is required to neutralise 1500 crr' of 0.1 N HCl? (N.-23)A)40 g13.B) 4 gCy6g

Answer»

Weight of NaOH = N* E.W. * V/1000

Put the values in the above formula

Weight of NaOH required.= 0.1 *40 *1500/1000

= 6 gm



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