How much of NaOH is required to neutralise 1500cm^(3) of 0.1 N HCl ? ( – InterviewSolution

1.	How much of NaOH is required to neutralise 1500cm^(3) of 0.1 N HCl ? (Na = 23)
Answer» 40 G 4 g 6 g 60 g Solution :`1500cm^(3)" of of 0.1 N HCl"-=(0.1)/(1000)xx1500="0.15 g eq."` It will neutralise `NaOH=0.15" g eq."=0.15xx40g=6g`

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