1.

How much quantity of electricity has to be passed through 200 mL of 0.5 M CuSO_(4) solution to completely deposite copper ?

Answer»

96500 C
`2 XX 9650 C`
`2 xx 96500 C `
`4 xx 96500 C`

Solution :200 ml of 0.5 M `CuSO_(4)` CONTAINS `CuSO_(4)` = 0.1 mole .
`Cu^(2+) + 2E^(-) to Cu`
To deposit 0.1 mole of `Cu^(2+)` , electricity required = `2XX 9650` C


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