1.

How much sulphur is present in organic compoundif on analysis 0.53 gmof thiscompound gives 1.158 gm of BaSO_(4).

Answer»

`10%`
`15%`
`20%`
`30%`

Solution :Percentage of sulphur
`= (32)/(233) xx (" MASS of" BaSO_(4))/(" mass of ORGANIC compound") xx 100`
`= (32)/(233) xx (1.158)/(0.53) xx 100 = 30%`.


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