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How much time would be needed to deposit 0.25 g of metallic nickel. (Atomic mass = 58.5) on a metal object using a current of 1A during electroplating? |
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Answer» Solution :`Ni^(++) + 2e^(-) to Ni` 2F or `2 xx 96500` C of electricity is required to deposit 58.5 g of Ni. 58.5 g of Ni REQUIRES `2 xx 96500` C 0.25 g Ni requires `=(2 xx 96500 xx 0.25)/58.5 = 824.8` C Amount of electricity = CURRENT in amperes `xx` time in SECONDS Time in seconds `=("Amount of electricity")/("Current in amperes")` `=824.8/1 = 824.8 sec = 13.74` MINUTES. |
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