1.

How much urea (molar mass = "60 g mol"^(-1)) should be dissolved in 50 g of water so that its vapour pressure at room temperature is reduced by 25%. Calculate molality of the solution obtained.

Answer»


Solution :If `p^(@)=100mm, p_(s)=75MM`. Hence, `=(100-75)/(100)=(w_(2)//60)/(50//18+w_(2)//60).` This gives `w_(2)=55.556g`
`"Molality of the solution "=(55.556//"60 mol")/(50 g)xx1000g KG^(-1)=18.52m`


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