How much urea must be dissolved in 10^(-2)m^(3) water to yield a press – InterviewSolution

1.	How much urea must be dissolved in 10^(-2)m^(3) water to yield a pressure is 2.03xx10^(5)Nm^(-2) at 300K?
Answer» 48.30 g 60.0 g 24.15 g 48.03 g Solution :OSMOTIC PRESSURE `=2.03xx10^(5)NM^(-2)` `pi=CRT` `2xx10^(5)=m/60xx1000=80.186xx60xx0.01g` in `0.01m^(3)=48.3gimplies1J=1Nm`

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