1.

How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms^(-1)` is 10 s?A. `10^(-3)`JB. `10^(4) J`C. `2xx10^(3) J`D. `4xx10^(4) J`

Answer» Correct Answer - B
(b) As, equation of motion is
`v=u+at implies20=0+axx10`
`20=axx10 implies a=2 m//s^(2)`
Now, distance `s=ut+(1)/(2)at^(2)`
`implies s=0+(1)/(2)xx2xx10xx10`
or `" " s=100 m
W=F.s = mas = 50xx2xx100=10^(4) J`


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