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How much work must work be done by a force on 50 kg body in order to accelerate it in the direction of force from rest to `20 ms^(-1)` is 10 s?A. `10^(-3)`JB. `10^(4) J`C. `2xx10^(3) J`D. `4xx10^(4) J` |
Answer» Correct Answer - B (b) As, equation of motion is `v=u+at implies20=0+axx10` `20=axx10 implies a=2 m//s^(2)` Now, distance `s=ut+(1)/(2)at^(2)` `implies s=0+(1)/(2)xx2xx10xx10` or `" " s=100 m W=F.s = mas = 50xx2xx100=10^(4) J` |
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