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How to draw a regular pentagon of side 6 cm and then a triangle of the same area ? |
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Answer» Answer: Step-by-step explanation: Take a regular pentagon of side 4cm
Angle at centre = 360/5 = 72
HALF the angle = 72/2 = 36
Tan 36 = 2/h (Where h = APOTHEM)
h = 2/Tan 36
= 2.75
Area = (½ x 4 x 2.75) x 5 = 27.53 cm2
A triangle of the same area:
Area = 1/2bh
27.53 = ½ x 4 x h
27.53 = 2h
h = 13.8 cm calculate the area- ∆FDG is the required triangle Area of pentagon ABCDE = Area of ∆ FDG = 1/2 ×9×6 = 27cm²
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