How to find product using suitable rearrangement of 5×3×2×7 – InterviewSolution

1.

How to find product using suitable rearrangement of 5×3×2×7

Answer»

210

Step-by-step explanation:

REARRANGE as 2x3x5x7

then first MULTIPLY 2x3=6

then mutiply 5x7=35

now mutiply 6x35=210

plz MARK my answer as BRAINLIEST if this is helpful to you

Discussion

No Comment Found

Related InterviewSolutions

What is Rational Numbers ??Where are you Bunny ?? What happen Any Problem Bro ಠ︵ಠ
Observe the following table and find x is directly proportional
What is Rational Numbers ?Answer if ur boy ? Answer if ur Ashrith Im serious
ABCD is a parallelogram if the ratio sides 3,:2and perimeter is 120 m the find the length of the sides of the parallelogram
6. Find the area of the following polygohABCDEF where AP = 2 cm, AQ = 4 cm,AR = 6 cm, AD = 10 cm, AS = 8 cm, andBP, FQ, CR and ES are perpendiculars todiagonal AD
5y+10=4y-10 then what is the answer
*5. How do the prashastis written by Harisena and Ravikirti throw light on the history of theGuptas and Harshavardhana?
The product of two number is 27 /2 .If one number is 23/5,find the other. with solution
Evalute the expression given below for ( m = - 2 ) & ( n = 6 ) 3m³ + 2m²n + n³
Evalute the expression given below for ( m = - 2 ) & ( n = 6 )m² - n²