1.

How will the radioactivity of a cobalt specimen change in two years? The half-life is 5.2 years.

Answer»


Solution :The activity of the specimen is EQUAL to the number of decays per unit time:
`Q=-(dN)/(dt)lamdaN`. The ratio of the activities is
`x=Q_(2)/Q_(1)=N_(2)/N_(1)=E^(-lamda(t_(2)-t_(1)))=2^(-(t_(2)-t_(1))/T)`
Knowing the half-life, we can easily compute the DECREASE in the activity.


Discussion

No Comment Found

Related InterviewSolutions