1.

How will you convert: Cl-(CH_2)_4-Cl into hexane-1, 6-diamine?

Answer»

SOLUTION :`CL-(CH_2)_4-Cl` is TREATED with EXCESS KCN and the dicyanide FORMED is reduced with `LiAlH_4`
`Cl-(CH_2)-Cloverset(2KCN)toNC-(CH_2)_4-CNoverset(LiAlH_4)toH_2N-(CH_2)_6-NH_2`


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