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How will you determine the rate constant for the decomposition of nitrogen pentaoxide in C C_(4). Decomposition of nitrogen pentoxide in C Cl_(4). |
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Answer» Solution :`N_(2)O_(5)overset(k_(1))rarr 2NO_(2)+(1)/(2)O_(2)` (i) At time t = 0, the volume of OXYGEN liberated is zero. (ii) LET `V_(t)` and `V_(oo)` be the measured volumes of oxygen liberated after the reactant has reacted in 't' time and at completion `(t=oo)`. (iii) Initial concentration of `N_(2)O_(5)` is PROPORTIONAL to total volume of oxygen liberated (i.e.,) `(V_(oo))`. (iv) `(V_(oo)-V_(t))` is proportional to undecomposed `N_(2)O_(5)` at time 't'. (v) `therefore k_(1)=(2.303)/(t)"log"(V_(oo))/((V_(oo)-V_(t)))sec^(-1)` |
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