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How will you distinguish 1^(@) and 2^(@) hydroxyl groups present in glucose ? Explain with reactions. |
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Answer» Solution :When oxidized by nitric ACID, glucose as well as gluconic acid yields dicarboxylic acid, saccharic acid. This indicates the presence of primary alcoholic `(-OH)` group in glucose. The secondary hydroxyl GROUPS NEED drastic conditions to oxidize. Thus, rest four -OH groups in glucose are secondary alcohol group. `{:(""CHO),("|"),(" "(CHOH)_(4)),("|"),(""CH_(2)OH):}overset("Oxidation")rarr underset("Saccharic acid")({:(""COOH),("|"),(" "(CHOH)_(4)),("|"),(""COOH):})overset("Oxidation")LARR underset("Gluconic acid")({:(""COOH),("|"),(" "(CHOH)_(4)),("|"),(""COOH):})` |
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