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How would you account for the following: Sulphur in vapour state exhibits paramagnetism. |
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Answer» Solution :In the VAPOUR state sulphur exists as `S_2` and not as `S_8`. The electronic configuration of S is : `3s^2 3p^(2) x 3p^1 y 3p^(1) Z ` There are 2 unpaired ELECTRONS in antibonding `pi**` ORBITALS due to which it is paramagnetic. |
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