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How would you justify that the relative lowering in vapour pressure is a colligative property ? |
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Answer» Solution :According to Raoult.s law , " the relative LOWERING of vapoure PRESSURE `((po-ps)/(po))` is equal to the MOLE fraction of the solute `(X_1 (n_1)/(n_1 + n_2))` `IMPLIES(po-ps)/(po)=X_1`.From the above equation it is clear that relative lowering of vapour pressure DEPENDS upon the concentration or number of molecules of solute present in the solution. |
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