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How would you prepare : (i) C_(6)H_(5)NH_(2) from C_(6)H_(5)NO_(2) (ii) CH_(3)NH_(2) from C_(2)H_(5)NH_(2) (iii) C_(2)H_(5)NH_(2) from CH_(3)NH_(2) |
Answer» Solution : (II) `C_(2)H_(5)NH_(2) overset(HNO_(2)) to C_(2)H_(5)OH overset ("O") underset(K_(2)Cr_(2)O_(7)//H_(2)SO_(4))to CH_(3)COOH overset(NH_(3)) toCH_(3)COONH_(4) overset(DELTA) underset(-H_(2)O) toCH_(3)CONH_(2) overset (Br_(2)//KOH) to CH_(3)NH_(2)` (iii) `CH_(3)NH_(2) overset (HNO_(2)) to CH_(3)OH overset(SOCI_(2)) to CH_(3)CI overset ("KCN") to CH_(3)CN overset("[H]") to CH_(3)CH_(2)NH_(2)` |
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