1.

Howmany faradays of electricityarerequired to deposit10gof calciumfrom molten calcium chloideusing inert electrodes ? (Molarmass of calcium =40 g mol^(-1))

Answer»

`0.5 F`
`1 F`
`0.25 F`
`2F`

Solution :Relatonship obtainedon combing faraday 's first and secondlaws
`W=ZQ=(E )/(F)xxxQ=(Q)/(F)xx(E )=(Q)/(F)xx(M)/(Z)`
`=(Ixxt)/(F)xx(M)/(Z)`
Here Z= electrochemical equivalent
Q = quantity of ELECTRICITY passed
E= equivalent MASS
M=atomic mass
Z= VALENCY of the metal
F = one faraday or 986500 C
given weightof calciumthat has to e DEPOSITED = 10 g z of the metal ion =2
molecular mass of calcuiu `=40 g "mol"^(-1)`
`W=(I.T)/(F)xx(M)/(Z), 10 =(I.T)/(F)xx(40)/(2)`
`(10xx2)/(40)` F=IT `rarr` 0.5 F = I.T
0.5 F of electricity is requiredto deposit10 gof calciumfrommolten calciumchloirideusieng inertelectrodes


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