1.

Howmanymolesof electronsarerequiredfor thereductionof (i)3 molesof Zn^(2+)to Zn (ii) 1 mol of Cr^(3+)to Cr? HowmanyFaradaysof electricitywill berequired in each case ?

Answer»


Solution :Given :forreductionof 3 mol `Zn^(3+)` to Zn
Numberof molesof electronsrequired = ?
Reductionhalfreaction.
`Zn^(2+)+ 2e^(-)to Zn`
`:. 1 ` moleof `Zn^(2+) ` requires 2molesof electrons
`:. `3 moles of `Zn^(2+) `willrequires`3xx2= 6`molesof electrons
`:' 1` moleof electrons= 1 F
`:. 6`mol ofelectrons = 6 F
(II)Given :Reductionof 1 molof `Cr^(3+) ` to Cr
REDUCTION HALFREACTION
`Cr^(3+) + 3e^(-)" to " Cr`

Hence1 moleof `Cr^(3+)`will require3 moleof electrons
`:' 1` moleof electrons`=1 F"" :. 3 ` Moleof electrons=3 F `


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