[ HUNDRED POINTS]Two adjacent sides of rectangle are 5 x+6 and 2 x + 6

1.	[ HUNDRED POINTS]Two adjacent sides of rectangle are 5 x+6 and 2 x + 66. Find its area if its perimeter is 186 cm (answer in square centimetre please)
Answer» $\displaystyle\huge\red{\underline{\underline{Solution}}}$ $\blacksquare \:$ *RECTANGLE* A rectangle is a quadrilateral where all angles are 90° OPPOSITE sides are equal Opposite sides are parallel TWO sides are greater than the other two $\blacksquare$ *FORMULA* *FOR* *PERIMETER* & *AREA* LET Length of the rectangle = x unit Width of the rectangle = y unit Then Perimeter = 2(x+y) unit Area = xy sq unit $\blacksquare \:$ *CALCULATION* Since the area to be DETERMINED in SQUARE Centimeters So the unit of side & perimeter must be centimeter Two adjacent sides of rectangle are 5x+6 cm and 2x + 66 cm So perimeter $= \:2 \{ (5x + 6) + (2x + 66) \} = 2(7x + 72) \: \: \: cm$ It is given that perimeter is 186 cm So $2(7x + 72) = 186$ $\implies \: 7x + 72 = 93$ $\implies \: 7x = 21$ $\therefore \: x \: = 3$ Hence Two adjacent sides of rectangle are (15+6) = 21 cm and (6 + 66 ) = 72 cm Hence the required area $= 72 \times 21 \: \: \: \: sq \: cm$ $= 1512 \: \: \: sq \: cm$