1.

Hybridization and shape of `XeF_(4)` isA. `sp^(3)d`, trigonal bipyramidalB. `sp^(3)`, tetrahedralC. `sp^(3)d^(2)`, square planarD. `sp^(3)d^(2)`, hexagonal.

Answer» Correct Answer - C
In `XeF_(4)`
No. of electrons around Xe = 8 + 4 = 12
No. of electrons pairs = 12/2 = 6
Hybridisation = `sp^(3)d^(2)`
Bond pairs = 4
Lone pairs = 6 - 4 = 2
Therefore, `XeF_(4)` is square planar.


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