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Hybridization and shape of `XeF_(4)` isA. `sp^(3)d`, trigonal bipyramidalB. `sp^(3)`, tetrahedralC. `sp^(3)d^(2)`, square planarD. `sp^(3)d^(2)`, hexagonal. |
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Answer» Correct Answer - C In `XeF_(4)` No. of electrons around Xe = 8 + 4 = 12 No. of electrons pairs = 12/2 = 6 Hybridisation = `sp^(3)d^(2)` Bond pairs = 4 Lone pairs = 6 - 4 = 2 Therefore, `XeF_(4)` is square planar. |
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