1.

Hybridization, shape and magnetic moment of K_(3)[Co(CO_(3))_(3)] is

Answer»

`d^(2)sp^(3)`, octahedral, 4.9 B.M.
`sp^(3)d^(2)`, octahedral, 4.9 B. M.
`DSP^(2)`, square planar, 4.9 B.M.
`sp^(3)`, tetrahedral, 4.9 B.M.

Solution :In each case, magnetic moment is 4.9 B.M. which shows that each of them has 4 unpaired electrons. Further, in the given complex, oxidation state of cobalt is +3. Hence, it will have `3d^(6)` configuration, i.e.,

Thus, hybridisation possible is `sp^(3)d^(2)`, i.e., outer ORBITAL (HIGH spin) octahedral complex.


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