1.

Hydrogen (""_(1)H^(1)). Deuterium (""_(1)H^(2)) singly ionised Helium and doubly ionised lithium (""_(3)Li^(6))^(++) all have one electron around the nucleus. Consider an electron transition from n= 2 to n=1. If the wavelengths of emited radiation are lambda_(1),lambda_(2),lambda_(3) and lambda_(4) respectively then approximately which one of the following is correct?

Answer»

`lambda_(1)=2lambda_(2)=3lambda_(3)=4lambda_(4)`
`4lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4`
`lambda_(1)=2lambda_(2)=2lambda_(3)=lambda_(4)`
`lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`

Solution :`1/LAMBDA=RZ^(2) (1/1^(2)-1/2^(2))`
`1/lambda=R(1)^(2) (3//4) , 1/lambda =R(1)^(2) (3//4)`
`1/lambda=R 2^(2) (3//4), 1/lambda_(4)=R 3^(2) (3//4)`
`1/lambda_(1)=(1)/(4lambda_(3))=(1)/(9 lambda_(4))=(1)/(lambda_(2))`
So, `lambda_(1)=lambda_(2)=4lambda_(3)=9lambda_(4)`


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