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1. |
Hydrogen atom in this ground state is excited by means of monochromatic radiation of wavelength `975Å`. How many different lines are possible in the resulting spectrum? Calculate the longest wavelength amongst them. You may assume the ionization energy for hydrogen atom is `13.6eV`A. Total number of lines in emission spectrum would be `6`.B. Energy difference between `3^(rd)` and `4^(th)` orbit is `0.66 eV`.C. longest wavelength is emission spectrum would be `1.875 mu m`.D. smallest wavelength in emission spectrum would be `975 Å`. |
Answer» Correct Answer - A::B::C::D | |